JEE Mains · Physics · STD 11 - 3.2 motion in plane
A ball of mass \(m\) is thrown vertically upward. Another ball of mass \(2\,m\) is thrown an angle \(\theta\) with the vertical. Both the balls stay in air for the same period of time. The ratio of the heights attained by the two balls respectively is \(\frac{1}{x}\). The value of \(x\) is \(.....\)
- A \(1\)
- B \(2\)
- C \(6\)
- D \(6\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
Time of flight is same vertical component of velocity is same \(H _{\max }\) is same
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