ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Fluid mechanics
  • JEE Mains 2023
  • Medium
  • Numerical

An air bubble of diameter \(6\,mm\) rises steadily through a solution of density \(1750\,kg / m ^3\) at the rate of \(0.35\,cm / s\). The co-efficient of viscosity of the solution (neglect density of air) is \(..........\,Pas\) (given, \(g =10\,ms ^{-2}\))

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(B) \(10\)

Step-by-step Solution

Detailed explanation

Since the bubble is moving at constant speed the force acting on it is zero.

\(B = F _{ V }\)

\(\frac{4}{3} \pi R ^3 \rho g =6 \pi \eta Rv\)

\(\eta=\frac{2 R ^2 \rho g }{9 v }=\frac{2 \times\left(3 \times 10^{-3}\right)^2 \times 1750 \times 10}{9 \times 0.35 \times 10^{-2}}=10\,Pas\)

Same subject
Explore more questions on app