JEE Mains · Physics · STD 11 - Fluid mechanics
- JEE Mains 2023
- Medium
- Numerical
An air bubble of diameter \(6\,mm\) rises steadily through a solution of density \(1750\,kg / m ^3\) at the rate of \(0.35\,cm / s\). The co-efficient of viscosity of the solution (neglect density of air) is \(..........\,Pas\) (given, \(g =10\,ms ^{-2}\))
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
Since the bubble is moving at constant speed the force acting on it is zero.
\(B = F _{ V }\)
\(\frac{4}{3} \pi R ^3 \rho g =6 \pi \eta Rv\)
\(\eta=\frac{2 R ^2 \rho g }{9 v }=\frac{2 \times\left(3 \times 10^{-3}\right)^2 \times 1750 \times 10}{9 \times 0.35 \times 10^{-2}}=10\,Pas\)
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