JEE Mains · Physics · STD 11 - 3.2 motion in plane
A projectile is projected at \(30^{\circ}\) from horizontal with initial velocity \(40\,ms ^{-1}\). The velocity of the projectile at \(t =2\,s\) from the start will be \(........\) (Given \(g =10\,m / s ^2\) )
- A \(20 \sqrt{3}\,ms ^{-1}\)
- B \(40 \sqrt{3}\,ms ^{-1}\)
- C \(20\,ms ^{-1}\)
- D Zero
Answer & Solution
Correct Answer
(A) \(20 \sqrt{3}\,ms ^{-1}\)
Step-by-step Solution
Detailed explanation
At \(t =2\) particle is at maximum height moving with velocity \(V =40 \cos 30^{\circ}=20 \sqrt{3}\,ms ^{-1}\).
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