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JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
The correct truth table for the given input data of the following logic gate is:
- A
Inputs Output A B C D Y 1 1 0 1 1 0 0 1 1 0 1 0 1 0 1 1 1 1 1 0 - B
Inputs Output A B C D Y 1 1 0 1 1 0 0 1 1 0 1 0 1 0 0 1 1 1 1 1 - C
Inputs Output A B C D Y 1 1 0 1 0 0 0 1 1 0 1 0 1 0 1 1 1 1 1 1 - D
Inputs Output A B C D Y 1 1 0 1 0 0 0 1 1 1 1 0 1 0 1 1 1 1 1 1
Answer & Solution
Correct Answer
(B) Inputs Output A B C D Y 1 1 0 1 1 0 0 1 1 0 1 0 1 0 0 1 1 1 1 1
Step-by-step Solution
Detailed explanation
\(\begin{aligned} Y & =(\overline{(\overline{A \cdot B}) \cdot(C+D)}=\overline{\overline{A \cdot B}}+(\overline{C+D}) \\ Y & =(A \cdot B)+(\overline{C+D})\end{aligned}\)
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