JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
Two coaxial solenoids of different radii carry current \(I\) in the same direction. Let \(\;{\overrightarrow {\;F} _1}\) be the magnetic force on the inner solenoid due to the outer one and \(\;{\overrightarrow {\;F} _2}\) be the magnetic force on the outer solenoid due to the inner one. Then
- A \(\;\overrightarrow {{F_1}} \) is radially inwards and \(\overrightarrow {{F_2}} \) is radially outwards
- B \(\;\overrightarrow {{F_1}} \) is radially inwards and \(\overrightarrow {\;{F_2}} \)\(=0\)
- C \(\overrightarrow {{F_1}} \) is radially outwards and \(\overrightarrow {\;{F_2}} =0\)
- D \(\overrightarrow {{F_1}} =\overrightarrow {\;{F_2}} =0\)
Answer & Solution
Correct Answer
(D) \(\overrightarrow {{F_1}} =\overrightarrow {\;{F_2}} =0\)
Step-by-step Solution
Detailed explanation
(Both solenoids are taken to be ideal in nature.) Both wires will attract each other, but net force on each wire will be zero. Concept: Two current carrying elements attract each other if direction of current is same. \(\overrightarrow {{F_1}} =\overrightarrow {\;{F_2}} =0\)
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