JEE Mains · Physics · STD 12 - Electric charges and fields
- JEE Mains 2020
- Medium
- MCQ
An electric dipole of moment \(\overrightarrow{\mathrm{p}}=(-\hat{\mathrm{i}}-3 \hat{\mathrm{j}}+2 \hat{\mathrm{k}}) \times 10^{-29}\; \mathrm{C} \cdot \mathrm{m}\) is at the origin \((0,0,0) .\) The electric field due to this dipole at \(\overrightarrow{\mathrm{r}}=+\hat{\mathrm{i}}+3 \hat{\mathrm{j}}+5 \hat{\mathrm{k}}\) (note that \(\overrightarrow{\mathrm{r}} \cdot \overrightarrow{\mathrm{p}}=0)\) is parallel to
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \((+\hat{i}+3 \hat{j}-2 \hat{k})\)
Step-by-step Solution
Detailed explanation
since \(\overrightarrow{\mathrm{r}}\) and \(\overrightarrow{\mathrm{p}}\) are perpendicular to each other
therefore point lies on the equitorial plane.
Therefore electric field at the point will be
antiparallel to the dipole moment.
i.e. \(\overrightarrow{\mathrm{E}} \|-\overrightarrow{\mathrm{p}}\)
\(\overrightarrow{\mathrm{E}} \|(\hat{\mathrm{i}}+3 \hat{\mathrm{j}}-2 \hat{\mathrm{k}})\)
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