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JEE Mains · Physics · STD 12 - Moving charges and magnetism
  • JEE Mains 2019
  • Medium
  • MCQ

A particle of mass \(m\) and charge \(q\) is in an electric and magnetic field given by \(\vec E = 2\hat i + 3\hat j ;\, B = 4\hat j + 6\hat k\) The charged particle is shifted from the origin to the point \(P(x = 1 ;\, y = 1)\) along a straight path. The magnitude of the total work done is

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Answer & Solution

Correct Answer

(B) \(5\,q\)

Step-by-step Solution

Detailed explanation

\({{\vec F}_{{\text{net }}}} = d\vec E + q(\vec v \times \vec B)\)

\( = (2q\hat i + 3q\hat i) + q(\vec v \times \vec B)\)

\(W = {{\vec F}_{net}} \cdot \vec S\)

\( = 2q + 3q\)

\( = 5q\)