JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A particle of mass \(m\) and charge \(q\) is in an electric and magnetic field given by \(\vec E = 2\hat i + 3\hat j ;\, B = 4\hat j + 6\hat k\) The charged particle is shifted from the origin to the point \(P(x = 1 ;\, y = 1)\) along a straight path. The magnitude of the total work done is
- A \((0.35)\,q\)
- B \(5\,q\)
- C \((2.5)\,q\)
- D \((0.15)\,q\)
Answer & Solution
Correct Answer
(B) \(5\,q\)
Step-by-step Solution
Detailed explanation
\({{\vec F}_{{\text{net }}}} = d\vec E + q(\vec v \times \vec B)\) \( = (2q\hat i + 3q\hat i) + q(\vec v \times \vec B)\) \(W = {{\vec F}_{net}} \cdot \vec S\) \( = 2q + 3q\) \( = 5q\)
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