JEE Mains · Physics · STD 12 - 3. current electricity
The energy dissipated by a resistor is \(10 \,mJ\) in \(1\,s\) when an electric current of \(2\, mA\) flows through it. The resistance is \(....... \Omega\) (Round off to the Nearest Integer)
- A \(3600\)
- B \(2800\)
- C \(2450\)
- D \(2500\)
Answer & Solution
Correct Answer
(D) \(2500\)
Step-by-step Solution
Detailed explanation
\(Q = i ^{2} RT\) \(R =\frac{ Q }{ i ^{2} t }=\frac{10 \times 10^{-3}}{4 \times 10^{-6} \times 1}=2500\,\Omega\)
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