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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2021
  • Easy
  • Numerical

The energy dissipated by a resistor is \(10 \,mJ\) in \(1\,s\) when an electric current of \(2\, mA\) flows through it. The resistance is \(....... \Omega\) (Round off to the Nearest Integer)

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Answer & Solution

Correct Answer

(D) \(2500\)

Step-by-step Solution

Detailed explanation

\(Q = i ^{2} RT\)

\(R =\frac{ Q }{ i ^{2} t }=\frac{10 \times 10^{-3}}{4 \times 10^{-6} \times 1}=2500\,\Omega\)

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