JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2021
- Easy
- Numerical
The energy dissipated by a resistor is \(10 \,mJ\) in \(1\,s\) when an electric current of \(2\, mA\) flows through it. The resistance is \(....... \Omega\) (Round off to the Nearest Integer)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(2500\)
Step-by-step Solution
Detailed explanation
\(Q = i ^{2} RT\)
\(R =\frac{ Q }{ i ^{2} t }=\frac{10 \times 10^{-3}}{4 \times 10^{-6} \times 1}=2500\,\Omega\)
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