JEE Mains · Physics · STD 12 - 3. current electricity
In the given circuit the value of \(\left|\frac{I_1+I_3}{I_2}\right|\) is
- A \(4\)
- B \(6\)
- C \(8\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(I_1=I_2=\frac{20-10}{10}=1\,A\) \(I_3=1\,A\) \(\left|\frac{I_1+I_3}{ I _2}\right|=2\)
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