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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2022
  • Medium
  • Numerical

In normal adjustment, for a refracting telescope, the distance between objective and eye piece is \(30\,cm\). The focal length of the objective, when the angular magnification of the telescope is \(2\) , will be \(.....cm\) 

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Answer & Solution

Correct Answer

(A) \(20\)

Step-by-step Solution

Detailed explanation

\(f _{0}+ f _{ e }=30\)

\(m =\frac{ f _{0}}{ f _{ e }}\)

\(2=\frac{ f _{0}}{ f _{ e }} \Rightarrow f _{0}=2 f _{ e }\)

So \(f _{0}+\frac{ f _{0}}{2}=30\)

\(f _{0}=20\,cm\)

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