JEE Mains · Physics · STD 11 - Gravitation
- JEE Mains 2020
- Medium
- MCQ
Consider two solid spheres of radii \(\mathrm{R}_{1}=1 \;\mathrm{m}\) \(\mathrm{R}_{2}=2\; \mathrm{m}\) and masses \(\mathrm{M}_{1}\) and \(\mathrm{M}_{2},\) respectively. The gravitational field due to sphere \((1)\) and \((2)\) are shown. The value of \(\frac{\mathrm{M}_{1}}{\mathrm{M}_{2}}\) is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\frac{1}{6}\)
Step-by-step Solution
Detailed explanation
Gravitational field on the surface of a solid sphere \(I_{g}=\frac{G M}{R^{2}}\)
By the graph
\(\frac{\mathrm{GM}_{1}}{(1)^{2}}=2\)
and \(\frac{\mathrm{GM}_{2}}{(2)^{2}}=3\)
On solving
\(\frac{\mathrm{M}_{1}}{\mathrm{M}_{2}}=\frac{1}{6}\)
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