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JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2021
  • Hard
  • MCQ

A sphere of mass \(2\,kg\) and radius \(0.5\, m\) is rolling with an initial speed of \(1 \,ms ^{-1}\) goes up an inclined plane which makes an angle of \(30^{\circ}\) with the horizontal plane, without slipping. How low will the sphere take to return to the starting point \(A\) ? (in \(second\))

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Answer & Solution

Correct Answer

(C) \(0.57\)

Step-by-step Solution

Detailed explanation

\(a =\frac{ g \sin \theta}{1+\frac{ I }{ mR ^{2}}}=\frac{5}{7} \times \frac{10}{2}=\frac{25}{7}\)

\(t =\frac{2 v _{0}}{ a }=\frac{2 \times 1 \times 7}{25}\)

\(=0.56\)

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