JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Three charges \(Q, +q\) and \(+q\) are placed at the vertices of a right -angle isosceles triangle as shown below. The net electrostatic energy of the configuration is zero, if the value of \(Q\) is

- A \(+q\)
- B \(\frac{{ - \sqrt 2 q}}{{\sqrt 2 + 1}}\)
- C \(\frac{{ - q}}{{1 + \sqrt 2 }}\)
- D \(-2q\)
Answer & Solution
Correct Answer
(B) \(\frac{{ - \sqrt 2 q}}{{\sqrt 2 + 1}}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{U}_{\text {Total }}=\frac{\mathrm{kQq}}{\mathrm{a}}+\frac{\mathrm{kq}^{2}}{\mathrm{a}}+\frac{\mathrm{kQq}}{\mathrm{a} \sqrt{2}}=0\) \(\Rightarrow Q=\frac{-q}{\left(1+\frac{1}{\sqrt{2}}\right)}\)
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