JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2022
- Hard
- Numerical
A parallel beam of light is allowed to fall on a transparent spherical globe of diameter \(30 \,cm\) and refractive index \(1.5\). The distance from the centre of the globe at which the beam of light can converge is________ \(mm\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(225\)
Step-by-step Solution
Detailed explanation
\(\frac{\frac{3}{2}}{ V }-\frac{1}{\infty}=\frac{\frac{3}{2}-1}{15}\)
\(\frac{3}{2 V }=\frac{1}{30}\)
\(V =45 \,cm\)
\(\frac{1}{ V }-\frac{3}{\frac{2}{15}}=\frac{1-\frac{3}{2}}{\frac{2}{-15}}\)
\(\frac{1}{ V }-\frac{1}{10}=\frac{1}{30}\)
\(\frac{1}{ V }=\frac{1}{10}+\frac{1}{30}=\frac{4}{30}\)
\(V =7.5\)
\(V =22.5\)
\(v =225 \,mm\)
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