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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2022
  • Hard
  • Numerical

A parallel beam of light is allowed to fall on a transparent spherical globe of diameter \(30 \,cm\) and refractive index \(1.5\). The distance from the centre of the globe at which the beam of light can converge is________ \(mm\)

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Answer & Solution

Correct Answer

(C) \(225\)

Step-by-step Solution

Detailed explanation

\(\frac{\frac{3}{2}}{ V }-\frac{1}{\infty}=\frac{\frac{3}{2}-1}{15}\)

\(\frac{3}{2 V }=\frac{1}{30}\)

\(V =45 \,cm\)

\(\frac{1}{ V }-\frac{3}{\frac{2}{15}}=\frac{1-\frac{3}{2}}{\frac{2}{-15}}\)

\(\frac{1}{ V }-\frac{1}{10}=\frac{1}{30}\)

\(\frac{1}{ V }=\frac{1}{10}+\frac{1}{30}=\frac{4}{30}\)

\(V =7.5\)

\(V =22.5\)

\(v =225 \,mm\)

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