JEE Mains · Physics · STD 12 - Current electricity
- JEE Mains 2022
- Medium
- MCQ
An aluminium wire is stretched to make its length, \(0.4 \,\%\) larger. Then percentage change in resistance is \(.....\,\%\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(0.8\)
Step-by-step Solution
Detailed explanation
\(R =\frac{\rho \ell}{ A }\)
\(\frac{\Delta R }{ R }=\frac{\Delta \ell}{\ell}-\frac{\Delta A }{ A }\)
\(\ell A = k\)
\(\frac{\Delta \ell}{\ell}+\frac{\Delta A }{ A }=0\)
\(\frac{\Delta R }{ R }=\frac{2 \Delta \ell}{\ell}\)
\(\frac{\Delta R }{ R }=2 \times 0.4=0.8 \%\)
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