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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2022
  • Medium
  • MCQ

An aluminium wire is stretched to make its length, \(0.4 \,\%\) larger. Then percentage change in resistance is \(.....\,\%\)

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Answer & Solution

Correct Answer

(C) \(0.8\)

Step-by-step Solution

Detailed explanation

\(R =\frac{\rho \ell}{ A }\)

\(\frac{\Delta R }{ R }=\frac{\Delta \ell}{\ell}-\frac{\Delta A }{ A }\)

\(\ell A = k\)

\(\frac{\Delta \ell}{\ell}+\frac{\Delta A }{ A }=0\)

\(\frac{\Delta R }{ R }=\frac{2 \Delta \ell}{\ell}\)

\(\frac{\Delta R }{ R }=2 \times 0.4=0.8 \%\)

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