JEE Mains · Physics · STD 11 - Newtons laws of motion
- JEE Mains 2022
- Medium
- MCQ
A monkey of mass \(50\,kg\) climbs on a rope which can withstand the tension \((T)\) of \(350\,N\). If monkey initially climbs down with an acceleration of \(4\,m / s ^{2}\) and then climbs up with an acceleration of \(5\,m / s ^{2}\). Choose the correct option \(\left( g =10\,m / s ^{2}\right)\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) Rope will break while climbing upward
Step-by-step Solution
Detailed explanation
F.B.D of monkey while moving downward
Using Newton's second law
\(mg - T = ma _{1}\)
\(500- T =50 \times 4 \Rightarrow T =300\,N\)
F.B.D of monkey while moving up
Using Newton's second law of motion
\(T - mg = ma _{2}\)
\(T -500=50 \times 5\)
\(T =750\,N\)
Breaking strength of string \(=350\,N\)
String will break while monkey is moving upward
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