JEE Mains · Maths · STD 12 - 5. continuity and differentiation
Consider the function \(f(x)=\frac{\mathrm{P}(\mathrm{x})}{\sin (\mathrm{x}-2)}, \quad \mathrm{x} \neq 2\) \(\quad \quad \quad \quad 7, \quad\quad\quad \mathrm{x}=2\) where \(P(x)\) is a polynomial such that \(P^{\prime \prime}(x)\) is always a constant and \(P(3)=9\). If \(f(x)\) is continuous at \(x=2\), then \(P(5)\) is equal to \(.....\)
- A \(41\)
- B \(40\)
- C \(39\)
- D \(71\)
Answer & Solution
Correct Answer
(C) \(39\)
Step-by-step Solution
Detailed explanation
\(f(x)=\frac{\mathrm{P}(\mathrm{x})}{\sin (\mathrm{x}-2)}, \quad \mathrm{x} \neq 2\) \(\quad \quad \quad \quad 7, \quad\quad\quad \mathrm{x}=2\) \(\mathrm{P}^{\prime \prime}(\mathrm{x})=\) const. \(\Rightarrow \mathrm{P}(\mathrm{x})\) is a 2 degree polynomial \(f(x)\) is cont.…
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