ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion

A man (mass \(= 50\, kg\)) and his son (mass \(= 20\, kg\)) are standing on a frictionless surface facing each other. The man pushes his son so that he starts moving at a speed of \(0.70\, ms^{-1}\) with respect to the man. The speed of the man with respect to the surface is ........ \(ms^{-1}\)

  1. A \(0.47\)
  2. B \(0.28\)
  3. C \(0.14\)
  4. D \(0.20\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(0.20\)

Step-by-step Solution

Detailed explanation

\(\begin{array}{l} \Rightarrow 0 = 50{V_1} - 20{V_2}\,and\,{V_1} + {V_2} = 0.7\\ \Rightarrow \,{V_1} = 0.2 \end{array}\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app