JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Consider a cylinder of mass \(M\) resting on a rough horizontal rug that is pulled out from under it with acceleration \('a'\) perpendicular to the axis of the cylinder. What is \(F_{friction}\) at point \(P\) ? It is assumed that the cylinder does not slip
- A \(Mg\)
- B \(Ma\)
- C \(\frac{Ma}{2}\)
- D \(\frac{Ma}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{Ma}{3}\)
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