ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion

A body of mass \(m_1\) moving with an unknown velocity of \(v_1 \hat i\) undergoes a collinear collision with a body of mass \(m_2\) moving with a velocity \(v_2 \hat i\) . After collision \(m_1\) and \(m_2\) move with velocities of \(v_3 \hat i\) and \(v_4 \hat i\) respectively. If \(m_2 = 0.5\, m_1\) and \(v_3 = 0.5\, v_1\) then \(v_1\) is:

  1. A \({v_4} - \frac{{{v_2}}}{2}\)
  2. B \({v_4} - \frac{{{v_2}}}{4}\)
  3. C \({v_4} - {v_2}\)
  4. D \({v_4} + {v_2}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \({v_4} - {v_2}\)

Step-by-step Solution

Detailed explanation

Applying linear momentum conservation…
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app