JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A metallic conductor of length \(1\; m\) rotates in a vertical plane parallel to east-west direction about one of its end with angular velocity \(5 \;rad / s\). If the horizontal component of earth's magnetic field is \(0.2 \times 10^{-4} \;T\), then emf induced between the two ends of the conductor is .............
- A \(5 \; \mu V\)
- B \(50 \; \mu V\)
- C \(5 \; mV\)
- D \(50 \; mV\)
Answer & Solution
Correct Answer
(B) \(50 \; \mu V\)
Step-by-step Solution
Detailed explanation
emf induced between the two ends \(=\frac{B_{H} \omega l^{2}}{2}\) \(\frac{0.2 \times 10^{-4} \times 5 \times 1}{2}=0.5 \times 10^{-4}=50 \times 10^{-6} \; V =50 \; \mu V\)
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