JEE Mains · Physics · STD 11 - 13. oscillations
Assume that the earth is a solid sphere of uniform density and a tunnel is dug along its diameter throughout the earth. It is found that when a particle is released in this tunnel, it executes a simple harmonic motion. The mass of the particle is \(100 g\). The time period of the motion of the particle will be (approximately) (take \(g =10\,ms ^{-2}\), radius of earth \(=6400\,km\) )
- A \(24\) hours
- B \(1\) hour \(24\) minutes
- C \(1\) hour \(40\) minutes
- D \(12\) hours
Answer & Solution
Correct Answer
(B) \(1\) hour \(24\) minutes
Step-by-step Solution
Detailed explanation
Let at some time particle is at a distance \(x\) from centre of Earth, then at that position field \(E=\frac{G M}{R^3} x\) \(\therefore \text { Acceleration of particle }\) \(\vec{a}=-\frac{ GM }{ R ^3} \overrightarrow{ x }\)…
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