\(1.0\,\Omega \) પ્રતિ \(cm\) અવરોધ ધરાવતા તારમાંથી \('A'\) શબ્દ બનાવવામાં આવે છે. આ શબ્દની બંને બાજુની લંબાઈ \(20\, cm\) અને વચ્ચેના આડા ભાગની લંબાઈ \(10\, cm\) છે. બે બાજુ દ્વારા બનતો ખૂણો \(60\) છે. બે બાજુના ખુલ્લા છેડાં વચ્ચેનો સમતુલ્ય અવરોધ કેટલા ............ \(\Omega\) થાય?

A \(50\)
B \(10\)
C \(36.7\)
D \(26.7\)

Verified Solution

Answer & Solution

Correct Answer

(D) \(26.7\)

Step-by-step Solution

Detailed explanation

For \(ADE\) \(\frac{1}{\mathrm{R}^{\prime}}=\frac{1}{2 \mathrm{x}}+\frac{1}{10}\) or \(\quad \mathrm{R}^{\prime}=\frac{20 \mathrm{x}}{10+2 \mathrm{x}}\) \(\mathrm{R}_{\mathrm{BC}}=\frac{20 \mathrm{x}}{10+2 \mathrm{x}}+20-\mathrm{x}+20-\mathrm{x}\) ....\((i)\) or…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From JEE Mains

Explore more questions on app