JEE Mains · Physics · STD 11 - Oscillations
- JEE Mains 2020
- Hard
- MCQ
A \(LCR\) circuit behaves like a damped harmonic oscillator. Comparing it with a physical springmass damped oscillator having damping constant \(\mathrm{b}\), the correct equivalence would be:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(\mathrm{L} \leftrightarrow \mathrm{m}, \mathrm{C} \leftrightarrow \frac{1}{\mathrm{k}}, \mathrm{R} \leftrightarrow \mathrm{b}\)
Step-by-step Solution
Detailed explanation
By \(kVL\)
\(-\mathrm{L} \frac{\mathrm{di}}{\mathrm{dt}}-\frac{\mathrm{q}}{\mathrm{C}}-\mathrm{iR}=0\)
\(\mathrm{L} \frac{\mathrm{d}^{2} \mathrm{q}}{\mathrm{dt}^{2}}+\frac{1}{\mathrm{C}} \mathrm{q}+\mathrm{R} \frac{\mathrm{dq}}{\mathrm{dt}}=0\)
for damped oscillator
net force \(=-\mathrm{kx}-\mathrm{bv}=\mathrm{ma}\)
\(\frac{m d^{2} x}{d t^{2}}+k x+\frac{b d x}{d t}=0\)
by comparing : Equivalence is
\(\mathrm{L} \rightarrow \mathrm{m}: \mathrm{C} \rightarrow \frac{1}{\mathrm{K}} ; \mathrm{R} \rightarrow \mathrm{b}\)
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