JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A force \(\overrightarrow{\mathrm{F}}=2 \hat{i}+\mathrm{b} \hat{j}+\hat{k}\) is applied on a particle and it undergoes a displacement \(\hat{i}-2 \hat{j}-\hat{k}\). What will be the value of \(b\), if work done on the particle is zero.
- A 0
- B \(\frac{1}{2}\)
- C 2
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & w=0 \\ & \therefore \quad \vec{F} \cdot S=0 \\ & (2 \hat{i}+b \hat{j}+\hat{k}) \cdot(\hat{i}-2 \hat{j}-\hat{k})=0 \\ & 2-2 b-1=0 \\ & b=\frac{1}{2}\end{aligned}\)
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