JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A galvanometer with its coil resistance \(25\,\Omega \) requires a current of \(1\,mA\) for its full deflection. In order to construct an ammeter to read up to a current of \(2\,A,\) the approximate value of the shunt resistance should be
- A \(2.5 \times {10^{ - 2}}\,\Omega \)
- B \(1.25 \times {10^{ - 3}}\,\Omega \)
- C \(2.5 \times {10^{ - 3}}\,\Omega \)
- D \(1.25 \times {10^{ - 2}}\,\Omega \)
Answer & Solution
Correct Answer
(D) \(1.25 \times {10^{ - 2}}\,\Omega \)
Step-by-step Solution
Detailed explanation
A ccording to question, current through galvanometer, \(\mathrm{I}_{\mathrm{g}}=1\, \mathrm{mA}\) Current through shunt \(\left(I-I_{g}\right)=2\, A\) Galvanometer resistance \(\mathrm{R}_{\mathrm{g}}=25\, \Omega\) Resistance of shunt, \(\mathrm{S}=?\)…
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