JEE Mains · Maths · STD 12 - 13. probability
Let \(X\) be a random variable such that the probability function of a distribution is given by \(P(X=\) 0) \(=\frac{1}{2}, \mathrm{P}(\mathrm{X}=\mathrm{j})=\frac{1}{3^{j}}(\mathrm{j}=1,2,3, \ldots, \infty)\). Then the mean of the distribution and \(\mathrm{P}(\mathrm{X}\) is positive and even) respectively are:
- A \(\frac{3}{4}\) and \(\frac{1}{9}\)
- B \(\frac{3}{4}\) and \(\frac{1}{16}\)
- C \(\frac{3}{8}\) and \(\frac{1}{8}\)
- D \(\frac{3}{4}\) and \(\frac{1}{8}\)
Answer & Solution
Correct Answer
(D) \(\frac{3}{4}\) and \(\frac{1}{8}\)
Step-by-step Solution
Detailed explanation
mean \(=\sum x_{i} p_{i}=\sum_{r=0}^{\infty} r \cdot \frac{1}{3^{r}}=\frac{3}{4}\) \(p(x\) is even \()=\frac{1}{3^{2}}+\frac{1}{3^{4}}+\ldots \infty\) \(=\frac{\frac{1}{9}}{1-\frac{1}{9}}=\frac{1}{8}\)
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