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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2018
  • Medium
  • MCQ

Light of wavelength \(550\, nm\) falls normally on a slit of width \(22.0 \times 10^{-5}\,cm\). The angular position of the second minima from the central maximum will be (in radians)

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Answer & Solution

Correct Answer

(A) \(\frac{\pi }{8}\)

Step-by-step Solution

Detailed explanation

If angular position of \(2^{nd}\) maxima from central maxima is \(\theta\) then

\(\sin \theta  = \frac{{(2n - 1)\lambda }}{{2a}}\)  \( = \frac{{3\lambda }}{{2a}}\)  \( = \frac{{3 \times 550 \times {{10}^{ - 9}}}}{{2 \times 22 \times {{10}^{ - 7}}}}\)

\(\therefore \,\,\theta  = \frac{\pi }{8}\,\,{\text{rad}}\)