JEE Mains · Physics · STD 12 - 10. Wave optics
Light of wavelength \(550\, nm\) falls normally on a slit of width \(22.0 \times 10^{-5}\,cm\). The angular position of the second minima from the central maximum will be (in radians)
- A \(\frac{\pi }{8}\)
- B \(\frac{\pi }{12}\)
- C \(\frac{\pi }{4}\)
- D \(\frac{\pi }{6}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi }{8}\)
Step-by-step Solution
Detailed explanation
If angular position of \(2^{nd}\) maxima from central maxima is \(\theta\) then \(\sin \theta = \frac{{(2n - 1)\lambda }}{{2a}}\) \( = \frac{{3\lambda }}{{2a}}\) \( = \frac{{3 \times 550 \times {{10}^{ - 9}}}}{{2 \times 22 \times {{10}^{ - 7}}}}\)…
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