JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2018
- Medium
- MCQ
Light of wavelength \(550\, nm\) falls normally on a slit of width \(22.0 \times 10^{-5}\,cm\). The angular position of the second minima from the central maximum will be (in radians)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(\frac{\pi }{8}\)
Step-by-step Solution
Detailed explanation
If angular position of \(2^{nd}\) maxima from central maxima is \(\theta\) then
\(\sin \theta = \frac{{(2n - 1)\lambda }}{{2a}}\) \( = \frac{{3\lambda }}{{2a}}\) \( = \frac{{3 \times 550 \times {{10}^{ - 9}}}}{{2 \times 22 \times {{10}^{ - 7}}}}\)
\(\therefore \,\,\theta = \frac{\pi }{8}\,\,{\text{rad}}\)
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