JEE Mains · Physics · STD 12 - 1. Electric charges and fields
A charge \(q\) is placed at the center of one of the surface of a cube. The flux linked with the cube is _______.
- A \(\frac{q}{4 \epsilon_0}\)
- B \(\frac{q}{2 \epsilon_0}\)
- C \(\frac{q}{8 \epsilon_0}\)
- D Zero
Answer & Solution
Correct Answer
(B) \(\frac{q}{2 \epsilon_0}\)
Step-by-step Solution
Detailed explanation
\(2 \phi=\frac{q}{\epsilon_0}\) \(\phi=\frac{q}{2 \epsilon_0}\)
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