JEE Mains · Physics · STD 11 - 4.2 friction
A car is moving on a horizontal curved road with radius \(50\,m\). The approximate maximum speed of car will be \(............\,ms^{-1}\), if friction between tyres and road is \(0.34.\left[\right.\) Take \(\left.g =10 ms ^{-2}\right]\)
- A \(3.4\)
- B \(22.4\)
- C \(13\)
- D \(17\)
Answer & Solution
Correct Answer
(C) \(13\)
Step-by-step Solution
Detailed explanation
\(f_s=\frac{m v^2}{r}\) For maximum speed in safe turning, \(f _{ s }= f _{ s } \max =\mu mg\) \(v _{\max } \text { (for safe turning }=\sqrt{\mu rg }\) \(=\sqrt{0.34 \times 50 \times 10} \approx 13\,m / s\)
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