JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
- JEE Mains 2026
- Easy
- MCQ
A brass wire of length 2 m and radius 1 mm at \(27^{\circ} C\) is held taut between two rigid supports. Initially it was cooled to a temperature of \(-43^{\circ} C\) creating a tension T in the wire. The temperature to which the wire has to be cooled in order to increase the tension in it to 1.4 T , is _________ \({ }^{\circ} C\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(-71\)
Step-by-step Solution
Detailed explanation
\( T=\alpha YA(27-(-43).....(i) \)
\( 1.4~T=\alpha YA(27-\theta) \) ....(ii)
using (ii)/(i)
\( 1.4=\frac{27-\theta}{70} \)
\( 27-\theta=98 \)
\(\therefore \theta=-71^{\circ} C\)
\( 1.4~T=\alpha YA(27-\theta) \) ....(ii)
using (ii)/(i)
\( 1.4=\frac{27-\theta}{70} \)
\( 27-\theta=98 \)
\(\therefore \theta=-71^{\circ} C\)
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