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JEE Mains · Physics · STD 11 - 10.2 transmission of heat

Two plates \(A\) and \(B\) have thermal conductivities \(84\,Wm ^{-1}\,K ^{-1}\) and \(126\,Wm ^{-1}\,K ^{-1}\) respectively. They have same surface area and same thickness. They are placed in contact along their surfaces. If the temperatures of the outer surfaces of \(A\) and \(B\) are kept at \(100^{\circ}\,C\) and \(0{ }^{\circ}\,C\) respectively, then the temperature of the surface of contact in steady state is \(..........\,{ }^{\circ} C\).

  1. A \(20\)
  2. B \(40\)
  3. C \(60\)
  4. D \(80\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(40\)

Step-by-step Solution

Detailed explanation

Let the temperature of contact surface is \(T\), then \(H _{ A }= H _{ B }\) \(\frac{ K _{ A } A\left(T_A-T\right)}{L}=\frac{ K _{ B } A \left( T - T _{ B }\right)}{ L }\) \(84(100-T)=126( T -0)\) \(2(100-T)=3\,T\) \(200-2\,T =3\,T\) \(T =40^{\circ}\,C\)
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