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JEE Mains · Physics · STD 11 - Transmission of heat
  • JEE Mains 2023
  • Medium
  • MCQ

A body cools in \(7\) minutes from \(60^{\circ}\,C\) to \(40^{\circ}\,C\). The temperature of the surrounding is \(10^{\circ}\,C\). The temperature of the body after the next \(7\) minutes will be

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Answer & Solution

Correct Answer

(C) \(28^{\circ}\,C\)

Step-by-step Solution

Detailed explanation

using average rate of Newton's law of cooling

\(\frac{T_1-T_2}{t}=K\left(\frac{T_1+T_2}{2}-T_s\right)\)

Given \(\frac{60-40}{7}=K(50-10) \ldots\) (i)

\(\frac{40-T}{7}=K\left(\frac{40+T}{2}-10\right) \ldots\) (ii)

From \((i)\) and \((ii)\)

\(T =28^{\circ}\,C\)

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