JEE Mains · Physics · STD 11 - Motion in straight line
- JEE Mains 2021
- Hard
- Numerical
A particle is moving with constant acceleration \('a'.\) Following graph shows \(v^{2}\) versus \(x\) (displacement) plot. The acceleration of the particle is \(......{m} / {s}^{2}\)

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Answer & Solution
Correct Answer
(D) \(1\)
Step-by-step Solution
Detailed explanation
\({y}={m} {x}+{C}\)
\({v}^{2}=\frac{20}{10} {x}+20\)
\({v}^{2}=2 {x}+20\)
\(2 {v} \frac{{d} {v}}{{d} {x}}=2\)
\(\therefore {a}={v} \frac{{d} {v}}{{d} {x}}=1\)
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