JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
An open glass tube is immersed in mercury in such a way that a length of \(8\ cm\) extends above the mercury level. The open end of the tube is then closed and sealed and the tube is raised vertically up by additional \(46\ cm\). What will be length of the air column above mercury in the tube now ....... \(cm\) ? ( Atmospheric pressure = \(76\ cm\) of \(Hg\))
- A \(22\)
- B \(38\)
- C \(6 \)
- D \(16 \)
Answer & Solution
Correct Answer
(D) \(16 \)
Step-by-step Solution
Detailed explanation
Length of the air column above mercury in the tube is, \(p + x = {P_0}\) \( \Rightarrow p = \left( {76 - x} \right)\) \( \Rightarrow 8 \times A \times 76 = \left( {76 - x} \right) \times A \times \left( {54 - x} \right)\) \(\therefore \,x = 38\) Thus, lenght of air column…
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