JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
\(100\) balls each of mass moving with speed \(v\) simultaneously strike a wall normally and reflected back with same speed, in time \(t s\). The total force exerted by the balls on the wall is
- A \(\frac{100 \,mv }{ t }\)
- B \(\frac{200\, mv }{ t }\)
- C \(200\,mvt\)
- D \(\frac{ mv }{100 t }\)
Answer & Solution
Correct Answer
(B) \(\frac{200\, mv }{ t }\)
Step-by-step Solution
Detailed explanation
\(P _{ i }= Nm v \hat{ i } \quad \overrightarrow{ P }_{ f }=- Nm v \hat{ i }\) \(N\) is Number of balls strikes with wall \(N =100\) \(\Delta \overrightarrow{ P } =\overrightarrow{ P }_{ f }-\overrightarrow{ P }_{ i }=-2 Nmv \hat{ i }\) \(=-200\,Nm v \hat{ i }\)…
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