JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
The temperature of an open room of volume \(30\ m^3\) increases from \(17^o C\) to \(27vC\) due to sunshine. The atmospheric pressure in the room remains \(1 \times 10^5\ Pa\). Ifni and nr are the number of molecules in the room before and after heating, then \(n_f-n_i\) will be :
- A \(-1.61 \times 10^{23}\)
- B \(1.38 \times 10^{23}\)
- C \(2.5 \times 10^{23}\)
- D \(-2.5 \times 10^{25}\)
Answer & Solution
Correct Answer
(D) \(-2.5 \times 10^{25}\)
Step-by-step Solution
Detailed explanation
\(\text { Given: Temperature } T_{i}=17+273=290 \mathrm{K}\) Temperature \(T_{f}=27+273=300 K\) Atmospheric pressure, \(P_{0}=1 \times 10^{5} P a\) \( Volume\, of\, room,\) \(V_{0}=30 \mathrm{m}^{3}\) \( Difference \,in\, number\, of\, molecules,\) \(N_{f}-N_{i}=?\) The number…
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