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JEE Mains · Physics · STD 12 - 3. current electricity

A \(220 \; V , 50 \; Hz\) AC source is connected to a \(25 \; V\), \(5 \; W\) lamp and an additional resistance \(R\) in series (as shown in figure) to run the lamp at its peak brightness, then the value of \(R\) (in ohm) will be

  1. A \(975\)
  2. B \(875\)
  3. C \(775\)
  4. D \(675\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(975\)

Step-by-step Solution

Detailed explanation

\(P = Vi\) \(5=25 i\) \(i=\frac{1}{5}\) \(V_{R}=i R\) \((220-25)=\frac{1}{5} R\) \(R=195 \times 5=975 \Omega\)
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