ExamBro
ExamBro
JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2022
  • Medium
  • Numerical

A \(220 \; V , 50 \; Hz\) AC source is connected to a \(25 \; V\), \(5 \; W\) lamp and an additional resistance \(R\) in series (as shown in figure) to run the lamp at its peak brightness, then the value of \(R\) (in ohm) will be

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(975\)

Step-by-step Solution

Detailed explanation

\(P = Vi\)

\(5=25 i\)

\(i=\frac{1}{5}\)

\(V_{R}=i R\)

\((220-25)=\frac{1}{5} R\)

\(R=195 \times 5=975 \Omega\)

Same subject
Explore more questions on app