JEE Mains · Physics · STD 12 - Electromagnetic waves
- JEE Mains 2023
- Medium
- MCQ
The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by \(E _{ x }= E _0 \sin ( kz -\omega t )\) \(B _{ y }= B _0 \sin ( kz -\omega t )\) Then the correct relation between \(E_0\) and \(B_0\) is given by
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(kE _0=\omega B _0\)
Step-by-step Solution
Detailed explanation
\(C =\frac{\omega}{ k }=\frac{ E _0}{ B _0}\)
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