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JEE Mains · Maths · STD 12 - 10. vector algebra

Let \(\vec{a}=\hat{i}+\hat{j}+2 \hat{k}, \vec{b}=2 \hat{i}-3 \hat{j}+\hat{k}\) and \(\overrightarrow{ c }=\hat{ i }-\hat{ j }+\hat{ k }\) be three given vectors. Let \(\vec{v}\) be a vector in the plane of \(\vec{a}\) and \(\overrightarrow{ b }\) whose projection on \(\overrightarrow{ c }\) is \(\frac{2}{\sqrt{3}}\). If \(\overrightarrow{ v } . \hat{ j }=7\), then \(\overrightarrow{ v } \cdot(\hat{ i }+\hat{ k })\) is equal to

  1. A \(6\)
  2. B \(7\)
  3. C \(8\)
  4. D \(9\)
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Answer & Solution

Correct Answer

(D) \(9\)

Step-by-step Solution

Detailed explanation

\(\overrightarrow{ v }=\lambda \overrightarrow{ a }+\mu \overrightarrow{ b }\) \(\vec{v}=\lambda(1,1,2)+\mu(2,-3,1)\) \(\vec{v}=(\lambda+2 \mu, \lambda-3 \mu, 2 \lambda+\mu)\) \(\overrightarrow{ v } \cdot \hat{ j }=7\) \(\lambda-3 \mu=7\)…
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