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JEE Mains · Physics · STD 11 - Waves and sound
  • JEE Mains 2013
  • Easy
  • Numerical

An engine approaches a hill with a constant speed. When it is at a distance of \(0.9\, km\), it blows a whistle whose echo is heard by the driver after \(5\, seconds\). If the speed of sound in air is \(330\, m/s\), then the speed of the engine is .... \(m/s\)

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Answer & Solution

Correct Answer

(D) \(30\)

Step-by-step Solution

Detailed explanation

Let after 5 sec engine at point \(C\)

\(t=\frac{A B}{330}+\frac{B C}{330}\)

\(5=\frac{0.9 \times 1000}{330}+\frac{\mathrm{BC}}{330}\)

\(\therefore \mathrm{BC}=750 \mathrm{m}\)

Distance travelled by engine in \(5\, sec\)

\(=900 \mathrm{m}-750 \mathrm{m}=150 \mathrm{m}\)

Therefore velocity of engine

\(=\frac{150 \mathrm{m}}{5 \mathrm{sec}}=30 \mathrm{m} / \mathrm{s}\)

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