JEE Mains · Physics · STD 11- 8. mechanical properties of solids
The increase in the pressure required to decrease the volume \((\Delta V)\) of water is \(6.3 \times 10^7\) N/m\(^2\). The percentage decrease in the volume is _____. (Bulk modulus of water \(= 2.1 \times 10^9\) N/m\(^2\).)
- A \(2\%\)
- B \(3\%\)
- C \(6\%\)
- D \(4\%\)
Answer & Solution
Correct Answer
(B) \(3\%\)
Step-by-step Solution
Detailed explanation
Bulk modulus is given by \(B = \dfrac{\Delta P}{-\dfrac{\Delta V}{V}}\) The fractional decrease in volume is \(-\dfrac{\Delta V}{V} = \dfrac{\Delta P}{B}\) Substituting the given values: \(-\dfrac{\Delta V}{V} = \dfrac{6.3 \times 10^7}{2.1 \times 10^9} = 3 \times 10^{-2}\) The…
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