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JEE Mains · Physics · STD 11 - System of particles and rotational motion
  • JEE Mains 2020
  • Hard
  • MCQ

Three solid spheres each of mass \(\mathrm{m}\) and diameter \(d\) are stuck together such that the lines connecting the centres form an equilateral triangle of side of length \(d\). The ratio \(\mathrm{I}_{0} / \mathrm{I}_{\mathrm{A}}\) of moment of inertia \(\mathrm{I}_{0}\) of the system about an axis passing the centroid and about center of any of the spheres \(\mathrm{I}_{\mathrm{A}}\) and perpendicular to the plane of the triangle is

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Answer & Solution

Correct Answer

(A) \(\frac{13}{23}\)

Step-by-step Solution

Detailed explanation

From parallel axis theorem

\(I_{0}=3 \times\left[\frac{2}{5} M\left(\frac{d}{2}\right)^{2}+M\left(\frac{d}{\sqrt{3}}\right)^{2}\right]=\frac{13}{10} M d^{2}\)

\(\mathrm{I}_{\mathrm{A}}=\mathrm{I}_{0}+3 \mathrm{M}\left(\frac{\mathrm{d}}{\sqrt{3}}\right)^{2}\)

\(=\frac{13}{10} \mathrm{Md}^{2}+\mathrm{Md}^{2}\)

\(=\frac{23}{10} \mathrm{Md}^{2}\)

\(\frac{\mathrm{I}_{0}}{\mathrm{I}_{\mathrm{A}}}=\frac{13}{23}\)

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