JEE Mains · Maths · STD 11 - 6. permutation and combination
The number of ways of giving \(20\) distinct oranges to \(3\) children such that each child gets atleast one orange is \(............\).
- A \(170\)
- B \(168\)
- C \(169\)
- D \(171\)
Answer & Solution
Correct Answer
(D) \(171\)
Step-by-step Solution
Detailed explanation
\(20\) distinct oranges distributed among \(3\) children so that each child gets at least one orange \(=3^{20}-{ }^3 C _1 2^{20}+{ }^3 C _2 1^{20}\) Bonus
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