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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

 The number of points, where the function \(f: R \rightarrow R , f ( x )=| x -1| \cos | x -2| \sin | x -1|+\) \((x-3)\left|x^{2}-5 x+4\right|\), is NOT differentiable, is.

  1. A \(1\)
  2. B \(2\)
  3. C \(3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(f(x)=|x-1| \cos |x-2| \sin |x-1|+(x-3) \mid x^{2}-5 x +4 \mid\) \(=|x-1| \cos |x-2| \sin |x-1|+(x-3)|x-1||x-4|\) \(=|x-1|[\cos |x-2| \sin |x-1|+(x-3)|x-4|]\) Non differentiable at \(x =1\) and \(x =4\).
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