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JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
If \(P = \left[ {\begin{array}{*{20}{c}}
{\frac{{\sqrt 3 }}{2}}&{\frac{1}{2}}\\
{ - \frac{1}{2}}&{\frac{{\sqrt 3 }}{2}}
\end{array}} \right],\,A = \,\left[ {\begin{array}{*{20}{c}}
1&1\\
0&1
\end{array}} \right]\) and \(Q=PAP^T,\) then \(P^T\) \(Q^{2015}\) \(P\) is
- A \(\,\left[ {\begin{array}{*{20}{c}}
0&{2015}\\
0&0
\end{array}} \right]\) - B \(\,\left[ {\begin{array}{*{20}{c}}
{2015}&0\\
1&{2015}
\end{array}} \right]\) - C \(\left[ {\begin{array}{*{20}{c}}
1&{2015}\\
0&1
\end{array}} \right]\) - D \(\left[ {\begin{array}{*{20}{c}}
{2015}&1\\
0&{2015}
\end{array}} \right]\)
Answer & Solution
Correct Answer
(C) \(\left[ {\begin{array}{*{20}{c}}
1&{2015}\\
0&1
\end{array}} \right]\)
Step-by-step Solution
Detailed explanation
\(P=\left[\begin{array}{cc}\frac{\sqrt{3}}{2} & \frac{1}{2} \\ -\frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right]\) \(P^{T}=\left[\begin{array}{cc}\frac{\sqrt{3}}{2} & \frac{-1}{2} \\ \frac{1}{2} & \frac{\sqrt{3}}{2}\end{array}\right]\) \(P P^{T}=P^{T} P=I\)…
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