JEE Mains · Maths · STD 11 - 8. sequence and series
For \(x \in R\), let \([x]\) denote the greatest integer \( \le x\), then the sum of the series \(\left[ { - \frac{1}{3}} \right] + \left[ { - \frac{1}{3} - \frac{1}{{100}}} \right] + \left[ { - \frac{1}{3} - \frac{2}{{100}}} \right] + .....+\left[ { - \frac{1}{3} - \frac{{99}}{{100}}} \right]\)
- A \(-135\)
- B \(-153\)
- C \(-133\)
- D \(-131\)
Answer & Solution
Correct Answer
(C) \(-133\)
Step-by-step Solution
Detailed explanation
\(\underbrace {\left[ { - \frac{1}{3}} \right] + \left[ { - \frac{1}{3} - \frac{1}{{100}}} \right] + ... + \left[ { - \frac{1}{3} - \frac{{60}}{{100}}} \right]}_{\left( { - 1} \right)67}\)…
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