JEE Mains · Maths · STD 11 - 8. sequence and series
For \(p, q \in R\), consider the real valued function \(f ( x )=( x - p )^{2}- q , x \in R\) and \(q >0\). Let \(a _{1}, a _{2}, a _{3}\) and \(a _{4}\) be in an arithmetic progression with mean \(P\) and positive common difference. If \(\left| f \left( a _{ i }\right)\right|=500\) for all \(i=1,2,3,4\), then the absolute difference between the roots of \(f ( x )=0\) is.
- A \(50\)
- B \(60\)
- C \(70\)
- D \(80\)
Answer & Solution
Correct Answer
(A) \(50\)
Step-by-step Solution
Detailed explanation
\(f(x)=0 \Rightarrow(x-p)^{2}-q=0\) Roots are \(p+\sqrt{q}, p-\sqrt{q}\) absolute difference between roots \(2 \sqrt{q}\). Now, \(\left|f\left(a_{i}\right)\right|=500\) Let \(a_{1}, a_{2}, a_{3}, a_{4} a_{r} a_{1} a+d, a+2 d, a+3 d\) \(\left|f\left(a_{4}\right)\right|=500\)…
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