JEE Mains · Maths · STD 11 - 5. linear inequalities
Let \(S=\left\{x \in[-6,3]-\{-2,2\}: \frac{|x+3|-1}{|x|-2} \geq 0\right\}\) and \(T =\left\{ x \in Z: x ^{2}-7| x |+9 \leq 0\right\}\). Then the number of elements in \(S \cap T\) is \(....\)
- A \(7\)
- B \(5\)
- C \(4\)
- D \(3\)
Answer & Solution
Correct Answer
(D) \(3\)
Step-by-step Solution
Detailed explanation
\(S \cap T =\{-5,-4,3\}\)
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