JEE Mains · Maths · STD 12 - 8. Application and integration
Let \(e\) be the base of natural logarithm and let \(f: \{1, 2, 3, 4\} \rightarrow \{1, e, e^2, e^3\}\) and \(g: \{1, e, e^2, e^3\} \rightarrow \left\{1, \dfrac{1}{2}, \dfrac{1}{3}, \dfrac{1}{4}\right\}\) be two bijective functions such that \(f\) is strictly decreasing and \(g\) is strictly increasing. If \(\phi(x) = \left[f^{-1}\left\{g^{-1}\left(\dfrac{1}{2}\right)\right\}\right]^x\), then the area of the region \(R = \{(x, y): x^2 \leq y \leq \phi(x), 0 \leq x \leq 1\}\) is:
- A \(\dfrac{3 - \log_e(2)}{3\log_e(2)}\)
- B \(\dfrac{1}{3\log_e(2)}\)
- C \(3 + \log_e(2)\)
- D \(\dfrac{3 + \log_e(2)}{2 + \log_e(3)}\)
Answer & Solution
Correct Answer
(A) \(\dfrac{3 - \log_e(2)}{3\log_e(2)}\)
Step-by-step Solution
Detailed explanation
Given \(f: \{1, 2, 3, 4\} \rightarrow \{1, e, e^2, e^3\}\) is a strictly decreasing bijective function. Arranging the domain and codomain in increasing order, we get \(f(1) = e^3\), \(f(2) = e^2\), \(f(3) = e\), and \(f(4) = 1\). Given…
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